Question

Using the fact that x*ln(x)=sqrt(x)^2*ln(sqrt(x)^2)
and that |sqrt(x)*ln(sqrt(x)|<=1

show that |x*ln(x)|<=2*sqrt(x) when 0 15 years ago

Answer 1

This is to prove that x*ln(x) ->0 as x->0^+

Answer 2

Use the fact that\[\ln (a^{b}) = b (\ln a)\]