Question

factor by grouping
63x^3-45x^2+56x-40

Answer 1

take commons from left two terms. and from right two terms.

Answer 2

that's the first step.

Answer 3

so it would be 63^3-45x^2 right?

Answer 4

nikkiem, you have no patience. I solved the first one you posted right after you left.

Answer 5

You need to figure out what the first 2 terms have in common and factor it out, then do the same for the 3rd and 4 th terms.

Answer 6

im so lost i get what you are saying saifoo.kan in a way how did you solve it

Answer 7

here are the two "groups" in parentheses\[(63x^3-45x^2)+(56x-40)\]

Answer 8

so i have to add them together???

Answer 9

Now, take the left part first.
try taking commons,

9x^2(7x - 5)

Answer 10

that would be 5103 i multiply 9^2 by 7

Answer 11

is that right?

Answer 12

o_O

Answer 13

9x^2(7x - 5) = (63x^3−45x^2)

Answer 14

we have broken the complex parts into smaller parts.

Answer 15

then waht do i do

Answer 16

figure out what the 3rd and 4th terms have in common and factor it out.

Answer 17

make by grouping those like 9*7 and 9*5 after 8*7 and 8*5

and will get (9x2 +8)(7x-5)