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Mathematics 7 Online
OpenStudy (anonymous):

evaluate: 20 Σ(5k^2+3k) k=1

OpenStudy (anonymous):

can you simply plug in 20

OpenStudy (anonymous):

i thought theres a formula u hav to use

OpenStudy (anonymous):

n(n+1)/2

OpenStudy (anonymous):

and n(n+1)(2n+1)/6

OpenStudy (anonymous):

yes you are right, we can break this up into two sums. One will be sum form 1 to 20 of 5k^2 (here you can pull out the 5 as a constant and then simply use the formula you wrote above for the first n squares). Then the other summ will be the sum form 1 to 20 of 3k (again pull of the 3 as a constant). Then add the two values you get

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