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(-27)^2/3 write the expression in radical notation B; evaluate the radical expression
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\[\sqrt[3]{-27^2}\] b. 9
B why is 9 when there is -27 ?
(-27)^2/3 = \[\sqrt[3]{(-27)^{2}}\] = \[\sqrt[2]{729}\] because (-27) * (-27) = 729
is it \[\huge{-27^{\frac{2}{3}}}\]or\[\huge{ \frac{-27^2}{3}}\]???
729 = 9^3 so \[\sqrt[3]{729} = \sqrt[3]{9^{3}} = 9\]
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