Question

Find an equation of teh line tangent to the curve
y=e^x *cosx at (0,1)

Answer 1

take the derivative, replace x by 0 to get the slope, and then use slope intercept form of the line

Answer 2

im confused when i take teh derivative what to do....i know f' = e^x and g' = -sinx
after putting it into the product rule i get
e^x (cosx) + e^x (-sinx).....do i replace it by 0 now?

Answer 3

yes

Answer 4

and since
\[\sin(0)=0, \cos(0)=1, e^0=1\] you get 1

Answer 5

ok...so then i use teh slop intercept form with the point (0,1) adn slope m=1 for the equation: y-1 = 1(x-0)...is taht teh equation of the line tangent to teh curve