2. A public health researcher examines the medical records of a large sample of men who died in 1999. Of this sample, she finds that 22.4% died with heart disease. Further, she finds that one third of the men in the sample had at least one parent with heart disease, and of this latter group, 32.7% died of heart disease.

a) What percentage of men in the sample died of heart disease and neither parent had heart disease?

Question

2.  A public health researcher examines the medical records of a large sample of men who died in 1999.  Of this sample, she finds that 22.4% died with heart disease.  Further, she finds that one third of the men in the sample had at least one parent with heart disease, and of this latter group, 32.7% died of heart disease.

a) What percentage of men in the sample died of heart disease and neither parent had heart disease?

amistre64 · Answer

22.4% of the sample group died with heart disease

1/3 of the sample group had AT LEAST one parent with heart disease

(1/3) 32.7% died of heart disease.

.........................................

What percentage of men in the sample 

died of heart disease AND neither parent had heart disease?

P(0 parents|disease) hmmm....

amistre64 · Answer

lets say there are 1000 in the group so that we can forgo the decimals:

224 of them died of heart disease

333 1/3 had AT LEAST one parent with, that leaves us with 
666 2/3 had NO parent with heart disease.

333 1/3
     .327
-------
  109  people died of disease with AT LEAST one parent having it

---------------------------------------

  224
-109
------
  115  are left that died of heart disease in this scenario

amistre64 · Answer

115/1000 = 11.5 %  if its right

amistre64 · Answer

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