Question

can any one tell me what's the reason/logic behind 7^0=1 and what is the case with 0^0?

Answer 1

0^0 is undefined

Answer 2

It is defined as \[7^{0}=1\] nobody can't change

Answer 3

1^1 =1
2^1 =1


1^0 =1
2^0= 1

0^0=?
0^0=?

Answer 4

yes, \[n^0=1\]as long as n is not equal to 0

Answer 5

0^1=?
0^0=?

Answer 6

0^1 = 0

Answer 7

Right

Answer 8

what's the reason behind 7^0=1 -^0=1 but 0^0=0 how????

Answer 9

0^0 is not 0

Answer 10

0 to any power is 0
any power of 0 is 1


so is 0^0 answer 1 or 0

we call it undefined

Answer 11

7 ^3 / 7^3 = 1 = 7^(3-3) = 7^0
therefore 7^0 = 1 -this is true for any number
except
0^0 which is indeterminate

Answer 12

Any number (except zero) divided by itself equals 1.
\[x ^{m}\div x ^{n} = x ^{m - n}\]
\[7 ^{m}\div 7 ^{n} = 1\]
\[7 ^{n}\div 7 ^{n} = 7 ^{n - n}\]\[1= 7^{0}\]

Answer 13

xerxes Cool Name

Answer 14

erratum:
\[7^{n}\div 7^{n} = 1\]

Answer 15

great work xerxes.

now explain the deal with 0^0

Answer 16

\[x ^{n}\div x ^{n} = x ^{0}\]
let x = 0... the quotient is 0^0. But the divisor is zero! and division by zero is NOT permissible in math. my teacher said NEVER DIVIDE BY ZERO.

Answer 17

that makes 0^0 indeterminate.