what relationship exists between the mass number of an element and the isotopes of that element
Well if you think about the mass of the atom there is a kind of relationship: The mass of the atom is determined by how mutch the isotopes weighs and the relative frequency of appearance. So if we for an example look at carbon, there are 2 natural isotopes: \[m \left(\begin{matrix}12 \\ 6\end{matrix}C\right)=12,00000000 u\] \[m \left(\begin{matrix}13 \\ 6\end{matrix}C\right)=13,00335483 u \] the two carbon isotopes occurs with the relative frequencies of 98.89% and 1.11% so the calculation is going to look like this: \[m(C) = 0,9889 . 12,00000000 u + 0,0111 . 13,00335483 u = 12,011 u\] This is precisely the value of the atomic mass of naturally occurring carbon.
that dot between the procent and the mass is a multiplication sign :P
You are familiar with isotopes right?
"Give the symbol and number of neutrons in one atom of: (to get "mass number", you must round the "atomic mass" to the nearest whole number) Show your calculations." and we do it for barium, bismuth and carbon.
and others lol
Some notation first: \[_{Z}^{A}E\] Here is: Z the number of protons. A the nukleon-number/nucleus-number (the number of both protons and nutrons) E the shorten of the atom name we are talking about. Out from the we may be able to make the following equation to determine the number of neutrons (N): \[A=N+Z <-> N=A-Z\] We asume that the atom found is in then form with the highest relative frequency of appearance and are then able to do the following: m(E)=m(N) + m(Z) + m(electron) but becuase m(electron)<< m(N) and m(e)<< m(Z) and we set m(N) and m(Z) =1 we can rewrite to the following: m(E)=m(N) + m(Z) = A
nevermind! my friends in the class before me, said that what she put was incorrect so we cant do this one :P
Lets see how it works: \[_{4}^{9}B\] \[N=9-4=5\] \[_{83}^{209}Bi\] \[N=209-83=126\] \[_{6}^{12}C\] \[N=12-6=6\]
Damn shame becuase it is damn easy :P
lol xD
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