Solve for x: x^2 + 24x + 90 = 0
Use the quadratic formula.
I don't understand the quadratic formula, the lessons aren't very helpful.
Use, \[x = \frac{-b \pm \sqrt{b^2-4ac }}{2a}\]
The value of a = 1 b = 24 c = 90/
INsert the values in their places to get the final numerical values.
To see an example, watch this slightly goofy guy: http://www.youtube.com/watch?v=s80J2dAUUyI
Oh okay hold on..
a is the coefficient of the x^2 value. b is the coefficient of the x value. c is the constant.
I got a strange answer. I don't know if it's right.
the answer will be "strange" in as much as it's not an integer.
Well i got \[-72 \pm \sqrt{3}\] Is that right or no?..
No, that can't be right because the -72 just has nothing to do with -b/2 where b = 24. And in fact it isn't right. Calculate it again.
No because the original equation i received was \[-12 \pm \sqrt{108}\]
Still no. First, what is b^2 - 4ac for a = 1 b = 24 c = 90
24^2 - 4(1)(90)
\[b^2 - 4ac = 24^2 - 4(90) = 216 \]
Oh I divided before i subtracted.
So what's your answer now?
\[-12 \pm \sqrt{18}\]
the -12 is right. the sqrt(18) isn't
Okay so then i'm not getting this.
\[ \frac{\sqrt{b^2 - 4ac}{2a} = \frac{\sqrt{216}}{2} = \sqrt{216/4} = \sqrt{54} = 3\sqrt{6} \]
hmm ... look like eqn editor is broken.
Haha yeah..
sqrt(b^2 - 4ac)/2a = sqrt(216)/2 = sqrt(216/4) = sqrt(54) = 3 sqrt(6)
Why sqrt(216/4) ??
because (1/x)sqrt(y) = sqrt(y/x^2)
Oh okay so then the answer is 3 plus or negative √6 ?..
No. I hate giving the answer, but I'm going to give it and ask you to make sure you can get it as well: \[-12 \pm 3 \sqrt{6}\]
Ohh! So i was right but it just needed to be simplified from √18 to 3√6?
\[\sqrt{18} \ne 3\sqrt{6}\]
so you were not right.
Okay never mind then.
just use your damn scientific calculator.
just use your brain actually because this isn't hard with some practice.
hey jamess
help me
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