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Mathematics 20 Online
OpenStudy (aravindg):

physics help

OpenStudy (anonymous):

whats up?

OpenStudy (aravindg):

its a question on 1 d motion

OpenStudy (anonymous):

put the question out.......

OpenStudy (aravindg):

wel a man walks with a uniform velocity v towards a lantern of height H from ground

OpenStudy (aravindg):

his height is h

OpenStudy (aravindg):

find the velocity of the tip of his shadow

OpenStudy (aravindg):

when i checked the answer key it is given V*(H-h/h) but i dont knw jow it is got

OpenStudy (jamesj):

Nice question. Let the man be distance D from the lamp and the length of his shadow L. Then H/(D+L) = h/d => DH = h(d+L) => L = (H-h)/h . D Now the only thing changing on the RHS is D. We know D is change at a rate of v so rate of change of L is (H-h)/h . v

OpenStudy (jamesj):

(formally, differentiate wrt time L = (H-h)/h . D )

OpenStudy (aravindg):

helppppppppppp

OpenStudy (jamesj):

What step don't you follow? Draw a diagram certainly to help.

OpenStudy (aravindg):

wait dont go away let me read

OpenStudy (aravindg):

and draw

OpenStudy (jamesj):

post a comment when you're ready and I'll come back.

OpenStudy (aravindg):

i am confused which is L and in fig

OpenStudy (aravindg):

can u show

OpenStudy (aravindg):

..........

OpenStudy (aravindg):

.................u thr?

OpenStudy (jamesj):

OpenStudy (aravindg):

hw=ey there is no small d in fig

OpenStudy (jamesj):

d = D. I'm using D

OpenStudy (jamesj):

H/(D+L) = h/D => DH = h(D+L) => L = (H-h)/h . D

OpenStudy (aravindg):

L = (H-h)/h . D (H-h)/h . i didnt get this

OpenStudy (aravindg):

??

OpenStudy (jamesj):

DH = h(D+L) => DH = Dh + Lh => Lh = DH - Dh => Lh = D(H-h) => L = (H-h)/h . D

OpenStudy (aravindg):

(H-h)/h . v that step

OpenStudy (jamesj):

Now differentiate both sides dL/dt = (H-h)/h . dD/dt = (H-h)/h . v

OpenStudy (aravindg):

wel how we know that this is vlocity of the shadow??

OpenStudy (aravindg):

at tip???????/

OpenStudy (jamesj):

because L is the length of the shadow so its derivative is its velocity.

OpenStudy (jamesj):

but only with respect to the man.

OpenStudy (aravindg):

d is length of shadow ryt?

OpenStudy (jamesj):

Yes, by defintion and look at the diagram. with respect to the lamp, the velocity of the the tip of the shadow is dL/dt + v = (H-h)/h v + v = H/h . v

OpenStudy (aravindg):

pls show the steps of that v w r to lamp

OpenStudy (aravindg):

some more

OpenStudy (jamesj):

because the man walking towards the lamp at velocity v

OpenStudy (jamesj):

Suppose you're walking a dog. You are walking at speed v. And he walking towards you RELATIVE TO YOU at a speed w. Then the dog is walking at speed of v + w

OpenStudy (jamesj):

if w = 0 then he is walking at a speed v and hence he doesn't get any closer or farther away

OpenStudy (aravindg):

confused :(

OpenStudy (jamesj):

Imagine walking a dog. You're walking at speed v. At what speed does he have to walk so he is not closer or farther away from you?

OpenStudy (aravindg):

v

OpenStudy (jamesj):

yes and what is his velocity relative to you?

OpenStudy (aravindg):

0

OpenStudy (jamesj):

Now imagine he is walking with velocity of w relative to you. What is his absolute velocity if you are walking with a velocity of v?

OpenStudy (aravindg):

w+v

OpenStudy (jamesj):

Right. So that is what is going here with the tip of the shadow. The shadow length D was defined relative to the position of the man.

OpenStudy (jamesj):

and we found dD/dt, the velocity of the tip of the shadow relative to the man.

OpenStudy (jamesj):

The other way to think about this is the position of the tip of the shadow. That position is L + D

OpenStudy (aravindg):

k

OpenStudy (jamesj):

hence the velocity of the tip of the shadow is \[\frac{d \ }{dt} (L + D) = \frac{dL}{dt} + \frac{dD}{dt} = v + \frac{H-h}{h} v = \frac{H}{h}v\]

OpenStudy (aravindg):

oh k bt in othr case y we dont find relative velocity ??

OpenStudy (jamesj):

dD/dt is the velocity relative to the man.

OpenStudy (aravindg):

oh i got it as lamp was at rest we dont consider relative velocity ryt??

OpenStudy (jamesj):

I think we can assume the lamp hasn't got legs, yes

OpenStudy (aravindg):

again dD/dt is absolute velocity??if it was v with respect to man it shuld be vi H-h/h *v

OpenStudy (aravindg):

v-(H-h)/h*v

OpenStudy (jamesj):

"a man walks with a uniform velocity v towards a lantern of height H from ground"

OpenStudy (jamesj):

Are the man and the tip of the shadow moving in opposite directions? No. So it's addition, not subtraction.

OpenStudy (aravindg):

y?????

OpenStudy (aravindg):

va- vb when same direction

OpenStudy (jamesj):

Why are the man and the tip of the shadow moving in the same direction?

OpenStudy (jamesj):

NO. Go back back to our dog example.

OpenStudy (aravindg):

in dog example absolute value of dog velocity was w+v

OpenStudy (aravindg):

but rel is va-vb

OpenStudy (jamesj):

yes. added. that's what we're doing here.

OpenStudy (aravindg):

but rel is va-vb we are finding relative here

OpenStudy (jamesj):

so it's dD/dt

OpenStudy (jamesj):

which is the relative veloiccity of the shadow tip

OpenStudy (aravindg):

vs-vman

OpenStudy (jamesj):

relative to the man that is, because D itself is measured relative to the man.

OpenStudy (aravindg):

oh k

OpenStudy (aravindg):

i hav another o ne question

OpenStudy (jamesj):

post it separately

OpenStudy (aravindg):

:)

OpenStudy (aravindg):

physicsss

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