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Solve. x2 – 10x = 5 Using the quadratic formula
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the quadrative equation is\[(-b \pm \sqrt{-b-4ac})/2a\] so just plug 1 for a -10 for b and -5 for c (because you subtract the five to make it equal to 0)
WHAT i made a mistakie it wasn't -b in the square root its a positive b SORRY!
It's okay... So A=1 B=10 C=5 then i would so -10 +_ square root of 10^2 - 4 (1) (5)/ 2(1)
c would equal -5
you should get \[(-1 \pm \sqrt{-10x^{2}-4(1)(-5)})/2(1)\]
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