Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

Why aren't these two quantified statements logically equivalent? ∃x(P(x) xor Q(x)) and (∃x(P(x)) xor (∃xQ(x))?

OpenStudy (anonymous):

I thought you could use distributive law in the first one to get the second but its asking to show that they aren't logically equivalent..

OpenStudy (anonymous):

The first statement says that there exists and x such that for that single x, exactly one of P or Q is true. The second statement is extremely limiting, such that if *any* x exists for which P is true, the there is no x for which Q is true. Where the first statement only says that there exists one x for which P is true and Q is false (or Q true P false).

OpenStudy (anonymous):

Is there any way to show it mathematically?

OpenStudy (anonymous):

A counter example, for the set of integers: P(x) is true if a number is odd Q(x) is true if a number is even The first statement is true for any integer x, since P(x) xor Q(x) is always true. For that same set of numbers ∃x(P(x)) is true ∃x(Q(x)) is true P xor Q is then false.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!