Question

Please Someone solve it

integration of(1-v)/(1+V`2)
v`2=V Square
denominator v is square

Answer 1

i think you have to first separate the integral:
1/(1+v^2) + v/(1+v^2), so the integral of the first term is ArcTan (v) and for the integral of the second term i recommend you to do a change of variable:
y= 1+v^2 so dy= 2v and v= dy/2
and then you substitute:
v/(1+v^2) = (1/2)(dy/y) and the integral is (1/2) (In y)
finally you plug in the initial variables:
(1/2)(In [1+v^2])
so the total integral is:
ArcTan (y) + (1/2)(In [1+v^2])