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Solve the system of equations by the substitution method. Choose one answer. a. (0, 14) b. (5, -1) c. infinite number of solutions d. no solution
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multiply the first one by 4 12 + 4y = 56 as you see you have two equations which are the same.. you can for example subtract one from another to get 0=0 which is true. infinite number of solutions
\[y=14-3x\] plug in y into the second equation so you have\[12x+4(14-3x)=56\] solve for x \[12x+56-12x=56 \] so that \[0=0\] . This is a true statement so you have an infinite amount of solutions
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