Question

A falling skydiver has a mass of 105 kg. What is the magnitude of the skydiver's acceleration when the upward force of air resistance has a magnitude that is equal to one-half of his weight?

Answer 1

Pop in and pop out..

F_free = m * g - F_air = m*a
F_air = 1/2*m

a = (105kg * 9.8 m/s^2 - .5*105)/105kg

a = 9.3 m/s^

Answer 2

^___^

Answer 3

hey.. mark me up with a metal.. I've been trying to pick them up today.. "Good Answer" thing.. :D

Answer 4

i got you :D

Answer 5

swweeeeettt.. :DD

Answer 6

lol

Answer 7

See me roll up.. on my Segway.....
*Guess I'm just too white and nerdy*

Answer 8

Hahahaha!

Answer 9

I'm actually listening to that song now.. :P

Answer 10

hey i dont quite understand it
why is it that
a = (105kg * 9.8 m/s^2 - .5*105)/105kg
and not
a = (mg - F_air)/105
= (mg - 0.5*mg)/105
= (105*9.8 - 0.5*105*9.8)/105
= 4.9 ms^-2

Answer 11

since F_air = 1/2 of his weight?

Answer 12

F_free = m * g - F_air = m*a
F_air = 1/2*m
So, for the first equation, you substitute the F_air to get the same equation just with the F_air substituted:
F_Free=m*g-(1/2*m) =m*a
Hope this helps!