This is a chemistry question but there's no chemistry group so I'll ask here. When a 6.50-g sample of solid sodium hydroxide dissolves in 100.0 g of water in a coffee-cup calorimeter, the temperature rises from 21.6 degrees C to 37.8 degrees C. Calculate delta H (in kJ/mol NaOH) for the solution process. Assume that the specific heat of the solution is the same as that of pure water.

Question

anonymous · Answer

I actually did this in a physics lab once...
I am trying to remember but I don't think I can. What's delta H? That term isn't the same in physics.. Change in energy?

anonymous · Answer

Only thing I have for you is Change in Thermal energy of the water.
Which is like 0.12214 kJ/Mol
I did this with M*c*(delta)T

unklerhaukus · Answer

there totally is a chemistry group - http://openstudy.com/groups/chemistry

unklerhaukus · Answer

$$\Delta H = mC \Delta t$$

anonymous · Answer

ahh.. so it was change in thermal energy.. Did I need to worry about Kelvin or just the change in temp taken care of it.. I say that because the unit's in my book are kinda confusing...

unklerhaukus · Answer

Change in temperature is equivalent in Celsius and Kelvin
1 degree Celsius = 1 Kelvin

anonymous · Answer

k.. figured.. stupid Knight book. :/

unklerhaukus · Answer

book generally dont have high intelligence