Question

integral of 1/x^2-4x+5 dx ????

Answer 1

is that an undernominator?

Answer 2

\[\frac{1}{x^2-4x+5}=\frac{1}{(x-2)^2+1}\]

Answer 3

looks to tan-1 up

Answer 4

how did you get from 1/x^2−4x+5 to 1/(x−2)^2+1 ?

Answer 5

...in algebra we learn about completing a square

Answer 6

ohhhhhh! Thank you :)

Answer 7

yep, when the bottom doesnt factor nicely for a decomp, try to complete the square so you can tan-1 up it