use a half- angle formula to find the exactly value of the expression...:
Sin5 pies/12... can someone help me step by step
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OpenStudy (anonymous):
Do you know the half-angle formulas?
OpenStudy (anonymous):
yes, i do...
OpenStudy (anonymous):
What's the formula for sin(x/2)?
OpenStudy (anonymous):
sin(x/2)=\[\pm \sqrt{1-cosx/2}\]
OpenStudy (anonymous):
Ok. You missed the parentheses around 1-cosx, but yes that checks out.
Now, you know how to find the sin of half of an angle. You need to find sin(5pi/12). Can you see how this formula might help?
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OpenStudy (anonymous):
sin(x/2)=\[\pm \sqrt{1-cosx/2}\]
OpenStudy (anonymous):
i dont know how to figure out:)..
OpenStudy (anonymous):
sin(x/2)=\[\pm \sqrt{1-cosx/2}\]
OpenStudy (anonymous):
in the unit circle dont have 5pi/12
OpenStudy (anonymous):
They give you a hint to use the half-angle formula. What is 5pi/12 half of?
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OpenStudy (anonymous):
75 degree right
OpenStudy (anonymous):
Yes, but leave it in terms of pi.
OpenStudy (anonymous):
Wait. 75 degrees is still half of the angle we want. And keep it in radians. So 5pi/12 is half the angle we want. So what angle is 5pi/12 half of?
OpenStudy (anonymous):
5pi/24
OpenStudy (anonymous):
Wrong way.
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OpenStudy (anonymous):
i dont know
OpenStudy (anonymous):
|dw:1318570748034:dw|5pi/12 is half of the angle I've marked with a ?. How big is that angle?