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if t=pi/4 what is cos and sin
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sin(1/4pi) = cos(1/4pi) = \[{ 1 \over 2} \sqrt{2}\]
\[\cos(\pi/4)\ \approx .99990605\] \[\sin(\pi/4)\approx .01370735\]
remember to put your calculator on radians
That's true, he did not specify one way or the other though.
fair enough, but when you see pi it's usually radians :)
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ok i have a similar question t=pi/2, what is cos, and sin...why would sin be cos(1/2pi)
look at the link I posted , the answer is there.
Yes, he is right. The sin value is the y value, and cos in the x value, using your unit circle, you can find the points needed.
fiddle, the link says pi/2 (0,1)...how can i interpet that with relevance to my question
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oh now that makes sense thx
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