Question

use Logarthmic Differentiation to solve: y=(sin(3x))^ln(x)

Answer 1

twig can u go back to my ? about jrotc

Answer 2

take natural log of both sides
\[\ln(y)=\ln[(\sin(3x))^{\ln(x)}]\]
using properties of log learned in algebra we can write
\[\ln(y)=\ln(x) \ln(\sin(3x))\]
now take derivative of both sides
\[\frac{y'}{y}=[\ln(x)]'\ln(\sin(3x)]+[\ln(x)][\ln(\sin(3x)]'\]

Answer 3

let me know if you need help with the rest

Answer 4

HEY JAMES

Answer 5

Twig are you a girl!!

Answer 6

myininaya I FINALLY got it thanks to you!!! Thanks a bunch! and bieberfan, yes I am

Answer 7

np