Question

For what value "c" is the function continuous on the interval: (-infinity, infinity)?

f(x) = {cx^2 + 8x, when x < 5
f(x) = {x^3 - cx, when x ≥ 5

Assume thats just one big bracket
I got c = 8/3. Is this right?

Answer 1

) An object is thrown upward from the edge of a tall building with a velocity of 10m/s. Where will the object be 3s after it is thrown? Take g = 10m/s^2

Answer 2

pls help me

Answer 3

@successboye79
I did, look at your post

Answer 4

Is this right?

Answer 5

I'm trying to figure it out...

Answer 6

set them equal to each other and solve for c

Answer 7

8/3 is not correct

Answer 8

What I did was I equated the one-sided limits together

Answer 9

So limit 5 as x approaches it from the left side = limit 5 as x approaches it from the right side

That would be:
cx^3 + 8x = x^3 - cx

Answer 10

c(5)^3 + 8(5) = (5)^3 - c(5)

Answer 11

25c + 40 = 125 - 5c

Answer 12

20c = 40 - 125

Answer 13

20c = 85

Answer 14

85/20 = c?

Answer 15

Is this correct?

Answer 16

\[cx^2+8x=x^3-cx\]\[cx^2+cx=cx(x+1)=x^3-8x=x(x^2-8)\]\[c=(x^2-8)/(x+1)\]we need this to be continuous at x=5 so...\[c=(25-8)/(5+1)=17/6\]

Answer 17

that took me way too long, I'm just waking up... :/