Question

4x^2=12x+40

Answer 1

\[4x^2=12x+40\]
\[x^2-3x-10=0\]
\[(x-5)(x+2)=0\]

\[x=5,-2\]

Answer 2

simplify by dividing 4
x^2 - 3x - 10 = 0
now factor - kira has done it aleady

Answer 3

set the equation to zero
4x^2 -12x -40 = 0
Divide by 4
x^2 - 3x - 10 = 0

(x - 5)(x+2) = 0
x= 5, -2

Answer 4

but how did you get x^2 - 3x - 10 ?

Answer 5

after you set the equation to zero, you can factor out a 4.