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Sigma Notation Determining sums ????
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\[\sum_{k=1}^{\infty} (1/10^{k}\]
\[\sum_{k=1}^{\infty} ( 3/ 10^{k} )\]
ok you actually know what this is without any work. we can do the work, but this is \[.3333=\overline{.3}\] which your recognize as \[\frac{1}{3}\]
but how do you do the work?
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you can use \[\sum_{k=1}^\infty ar^k=\frac{a}{1-r}\] in this case \[a=\frac{3}{10},r=\frac{1}{10}\] so you get \[\frac{\frac{3}{10}}{1-\frac{1}{10}}=\frac{\frac{3}{10}}{\frac{9}{10}}=\frac{3}{9}=\frac{1}{3}\]
how do you get the r ?
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