A 71.0kg fireman slides down a 4.73 meter pole by applying 350. N against the pole with his hands. If he slides from rest, how fast is he moving when he reaches the ground?

Question

A 71.0kg fireman slides down a 4.73 meter pole by applying 350. N against the pole with his hands.  If he slides from rest, how fast is he moving when he reaches the ground?

anonymous · Answer

taking gravity as 9.8m/s^2
weight of man = 71.0*9.8
                      = 695.8N
Resultant force = weight of man - force the man applies
                       = 695.8 - 350
                       = 345.8N
total amount of energy = Force*distance
                                  = 345.8*4.73
                                  = 1636J
KE = 1636J
     = 0.5*m*v^2
therefore, speed = (1636/30.5)^0.5
                         = 7.32 m/s

anonymous · Answer

i dont know if this is correct because i am only in middle school

anonymous · Answer

I think you are correct.

anonymous · Answer

oh
thanks