Question

x^2+y^2+4x+6y-40=0
x-y=10

Answer 1

i need solution

Answer 2

x=5, y = -5 and x=0, y=-10

Answer 3

solution

Answer 4

\[x^2+y^2+4x+6y-40=0 ---(1)\]
\[x = y + 10---(2)\]
Sub (2) into (1):
\[(y+10)^2+y^2+4(y+10)+6y-40=0\]
\[y^2+20y+100+y^2+4y+40+6y-40=0\]
\[2y^2+30y+100=0\]
\[(y+5)(y+10)=0\]
\[y = -5 OR y = -10\]
Substitute y = -5
\[x = -5+10 = 5\]
Substitute y = -10
\[x = -10+10 = 0\]
So, x = 5, y = -5 OR x = 0, y = -10