x^2+y^2+4x+6y-40=0… - QuestionCove
OpenStudy (anonymous):

x^2+y^2+4x+6y-40=0 x-y=10

6 years ago
OpenStudy (anonymous):

i need solution

6 years ago
OpenStudy (anonymous):

x=5, y = -5 and x=0, y=-10

6 years ago
OpenStudy (anonymous):

solution

6 years ago
OpenStudy (kira_yamato):

$x^2+y^2+4x+6y-40=0 ---(1)$ $x = y + 10---(2)$ Sub (2) into (1): $(y+10)^2+y^2+4(y+10)+6y-40=0$ $y^2+20y+100+y^2+4y+40+6y-40=0$ $2y^2+30y+100=0$ $(y+5)(y+10)=0$ $y = -5 OR y = -10$ Substitute y = -5 $x = -5+10 = 5$ Substitute y = -10 $x = -10+10 = 0$ So, x = 5, y = -5 OR x = 0, y = -10

6 years ago