Question

determine the values of x using a x and y chart and the equation 2(x-3)^2 i need x and y coordinates

Answer 1

I assume you mean
y=2(x-3)^2

to find the y-intercepts, set x=0:
y=2(-3)^2=18

to find x-intercepts set y=0:
0=2(x-3)^2
x=3
the vertex is (3,0)

Answer 2

sorry i mean f(x)=2(x-3)^2=2x-2 determine the c values that solve the equation

Answer 3

???????
you mean solve
2(x-3)^2=2x-2
for x and call that number c?
what is c? it's not in the equation.

Answer 4

:D yeah umm the only thing it says is f(x)=2(x-3)^2=2x-2

Answer 5

well all I can think to do is solve for x, you want me to do that?

Answer 6

yes please

Answer 7

thak you by the way

Answer 8

Thank* you u been so helpful btw this is when you plug in numbers for x also

Answer 9

mulptiply out the exponent:\[2(x-3)^2=2x-2=2(x^2-6x+9)\]divide it all by 2:
\[x-1=x^2-6x+9\]collect like terms:\[x^2-7x+10=0\]factor:\[(x-5)(x-2)=0\]\[x=\left\{ 2,5 \right\}\]

Answer 10

Thank you

Answer 11

I'm not sure what you mean by "this is when you plug in numbers for x", but if you plug in the values above for x you get (0)x(0)=0
so that verifies our work.

Answer 12

ohhh thank you