Question

Hector is preforming a chemistry experiment that requires 140 milliliters of a 30% copper sulfate solution. he has a 25% copper sulfate solution and a 60% copper sulfate solution. How many milliliters of each solution should he mic to obtain the needed solution?

Answer 1

There is a specific portion of this site for Chemistry. You might get better help over there.

Answer 2

ok thanks! ill try that

Answer 3

this is an algebra word problem

Answer 4

yea there wasnt a chemistry section anyways.... :) thanks for trying tho

Answer 5

Yeah. Sorry bro/girl.

Answer 6

I am a dumb dumb.

Answer 7

yea there wasnt a chemistry section anyways.... :) thanks for trying tho

Answer 8

its ok you tried to help

Answer 9

amount@25%=140(.30-.60)/(.25-.60) = 120

leaving 20 for the 60%

Answer 10

yea there wasnt a chemistry section anyways.... :) thanks for trying tho

Answer 11

ok ill try that

Answer 12

i find the whole substitution equations and eliminations rather laborious, so I just go straght for it :)

Answer 13

i love the one step method. no muss, no fuss!

Answer 14

satellite73 how would you solve this?

Answer 15

just wish i understood it better

Answer 16

i would say "put amount of 60% copper solution as x, then since the total is 140 the amount of 25% solution must be 140 - x" then solve
\[.6x+.25(140-x)=.3\times 140\] but i really do like the other way better

Answer 17

ok thank you! :) everyone says im different and i like to learn algebra in a different way so this way is easyer for me... :)

Answer 18

is that .3 times 140 or .3x times 140?

Answer 19

a + b = 140 ; *-.60
a(.60) + b(.25) = 140(.30)

-a(.60) +b(-.60) =140(-.60)
a(.60) + b(.25) = 140(.30)
---------------------------
b(.25-.60) = 140(.30-.60)

b @ 25% = 140(.30-.60)/(.25-.60)