Question

In △JKL, KM is an altitude.
What is the length, in units, of JK?
5 radical 10, 10, 10 radical 5, or 15?

Answer 1

set up 3 pythagorean equations then sub them into eachother so you only have numbers and JK left n solve for JK

Answer 2

Can you tell me with a bit more steps please. My lesson really does not give me enough information.

Answer 3

ill give you the 3 equations 1 sec

Answer 4

\[JK^2=20^2+KM^2\]
\[25^2=JK^2+KL^2\]
\[KL^2=KM^2+5^2\]

Answer 5

Does that mean it would be 10 radical 5?

Answer 6

i got 5 radical 10

was you last equation
\[JK= \sqrt{(20^2+25^2-5^2)/2}\]

Answer 7

Oh so I did something a bit backwards.