a crazy apartment tenant throws a flower pot at a passing stranger 320 feet below on the street. assuming the flower pot is thrown with an initial velocity of 16 feet per second, how fast is it traveling when it (misses the stranger) an hits the street?

Question

anonymous · Answer

and were supposed to use -32 for acceleration

anonymous · Answer

Vf^2=Vi^2+2a(Xf-Xi)

Vf^2=(16)^2+2(9.8)(320)

Vf=80.80ft/s downwards or -80.80ft/s

anonymous · Answer

oops. replace 32 for 9.8

anonymous · Answer

wow thanks a lot

anonymous · Answer

you get 144ft/s downwards

anonymous · Answer

okay thank you!

anonymous · Answer

give me a medal. =D

anonymous · Answer

so why did you square the initial and final velocities? --ajain's friend

anonymous · Answer

that's one of the first formula's you're taught. you should be able to derive it from the position equation I believe, but I don't remember how to do that. =/

anonymous · Answer

oh thats ok i was just curious i figured it was just part of the equation