Question

what does 5√3 means?

Answer 1

5 square root 3.

Answer 2

That question seems philosophical...

Answer 3

it could be the 5th root of 3 too !

Answer 4

true true!

Answer 5

√ = square root

therefore it means
5 square root 3

Answer 6

It couldnt be fifth root of 3.

Answer 7

no that symbol only means root !

Answer 8

yes but it is written quite wring technically, and could be interpreted either way
people write x2 for x^2 here all the time.

Answer 9

The sum of the first n consecutive odd whole numbers i y, where n>0. √y-n =?

Answer 10

is y*

Answer 11

I really don't understand the question now. You mean a sum with a sigma sign?

Answer 12

root(y - n) = (n-1)root(n)

Answer 13

fifth root of 3 is ====> 1.24573094

Answer 14

\[\sqrt{y-n} - (n-1)\sqrt{n}\]

Answer 15

minus or equals?
and what are you doing, can you explain at all?

Answer 16

@harkirat

Answer 17

Yes, i will.
Just wait a few minutes.... I am preparing it......

Answer 18

The sum of the first n consecutive odd whole numbers i y, where n>0. √y-n =?
take first two odd whole numbers --- 1 and 3 so n=2
y = 1+ 3 = 4
y - n = 4-2 = 2
root(y-n) = root(2) = (2-1)root(4) i.e (n-1)root(n)

Answer 19

take first five consecutive odd whole numbers --- 1, 3, 5, 7 and 9 so n=5
y = 1+3+5+7+9 = 25
y - n = 25-5 = 20
root(y-n) = root(20) = 4 root(5) = (5-1)root(5) i.e (n-1)root(n)

Answer 20

Is the logic clear now...????

Answer 21

Sorry I made a mistake in the equation !!!!\[\sqrt{y-n} = (n - 1)\sqrt{n}\]

Answer 22

but the choices are...

A. n
B.-n
C.-y
D.0
E. It cannot be determined by the information givin

Answer 23

In your question is it Root(y - n) or root(y) - n ????

Answer 24

\[\sqrt{y - n} or \sqrt{y} - n\]

Answer 25

Question hai..
The sum of the first n consecutive odd whole numbers is y, where n>0. √y-n

Answer 26

question is..
The sum of the first n consecutive odd whole numbers is y, where n>0. √y-n

Answer 27

@harkirat, that's very interesting, thanks!

Answer 28

@mathshasproblems

Are u from india ?? I guess because you used the word "hai".....
I'm also from India (Delhi)..

Answer 29

@TuringTest

Just struck me.......after I wrote it on paper and tried to find a pattern....

Answer 30

It could also be
\[\sqrt{28}\]

Answer 31

Got the answer !!!!!

Answer 32

The answer is D. 0

Answer 33

I think we have to find \[\sqrt{y}-n = ?\]
The sum of the first n consecutive odd whole numbers i y, where n>0. √y-n =?

take first two odd whole numbers --- 1 and 3 so n=2
y = 1+ 3 = 4
root(y) = root(4) = 2
so root(y) - n = 2-2 = 0

take first five consecutive odd whole numbers --- 1, 3, 5, 7 and 9 so n=5
y = 1+3+5+7+9 = 25
root(y) = root(25) = 5
so root(y) - n = 5-5 = 0

Answer 34

Nice, though the other problem seemed harder. Hat's off to you Harkirat.

Answer 35

@TuringTest

Thanks for yr nice comment..☺☺
Once he sent the answers, I just had to check again and yes it is very simple this time!!