Question

find f'(-3) if f(x)=x^3/5-10x

Answer 1

-27/5+30
-27/35

Answer 2

-.7714

Answer 3

Differentiate to get:
\[f'(x)=\frac{3x^2}{5}-10\]
Then substitute -3 in for x:
\[f'(-3)=\frac{3(-3)^2}{5}-10=\frac{27}{5}-10=-4 \frac{3}{5}\]