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differentiate y=5tan(nx) where n is a positive integer. i know the derivative of 5tan(x) would be 5(sec(x))^2 but i dont know how the n fits in.
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use chain rule.
erg \[y'= 5n*sec^2(nx)\]
ohh i see, thanks
5 is a constant multiple, so you leave it alone. The derivative of tan(nx) = sec^2(nx), but then you have to multiply with the derivative of the inside which is derivative of nx. Since n is a number the derivative of nx = x.
derivative of nx = n ... not x. sorry
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if it is the case of 5tanx then you can do the same, but now derivative of x = 1, so you don't include 1 most of the time.
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