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OpenStudy (anonymous):
soooooo
y=16-2x
so put that within the equation
A=x(16-2x)
A=16x-2x^2
taking the derivative of a you get
A'(x)=16-4x
when A'= 0 you get -16=-4x
4=x
if x = 4
y=16-2(4)= 8
x=4
y=8
OpenStudy (anonymous):
you can check if you want
if x=1 y =14 A=14
if x=2 y= 12 A=24
...... on and on
OpenStudy (anonymous):
hope this helps
OpenStudy (anonymous):
=]
OpenStudy (anonymous):
but what is the answer or maximum. I was told to maximize it.
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OpenStudy (anonymous):
I also got x=4 and y=8 but I still don't know what the answer is
OpenStudy (anonymous):
how do you get A=24 if x=2??? A= 16-4(2)=2???? no it equals 8, check your math
OpenStudy (anonymous):
2(2)+y=16
4+ y = 16
y=12
so if y = 12 wen x =2, you get xy=2*12 = 24
OpenStudy (anonymous):
answer to maximum is x=4 y = 8
OpenStudy (anonymous):
i'm saying if you aren't sure you can check all the possibles since your number are actually really small it'd be like only 8 or so calculations
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