Question

The product of two positive numbers is 64. Find the numbers that have the least sum.

Answer 1

x*y = 64

try having both x and y be the same number, so that their product is 64 and the sum is 16

Answer 2

xy=64
x+y=s

y=64/x

x+(64/x)=s

x+(64x^-1)=s

1-64x^-2=s

1-64x^-2=0

x=+-8

Answer 3

-8 is not within are given domain or field therefore 8 is your answer.... so 8=x y=8

Answer 4

from
1-64x^-2=s how did you jump to
1-64x^-2=0 would u tell me Outkast3r09

Answer 5

from 1-64x^-2 is the derivative

a maximum or minimum occurs when the derivative is equal to zero

Answer 6

it should read 1-64x^-2=s' but i forgot the prime symbol