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Mathematics 18 Online
OpenStudy (anonymous):

factor by grouping x^3+8x^2-6x-48

OpenStudy (anonymous):

okay factor by grouping, how would you start?

OpenStudy (anonymous):

put stuff together

OpenStudy (anonymous):

Put stuff together, thats funny i'll give you your first step: (x^3+8x^2)-(6x-48)

OpenStudy (anonymous):

how does 6x go with -48?? 48 doesnt have an x??

OpenStudy (anonymous):

focus on coefficients, not x

OpenStudy (anonymous):

ok..

OpenStudy (anonymous):

.........

OpenStudy (anonymous):

from the step i gave you, factor

OpenStudy (anonymous):

im really not sure how to do this but I get 8x^5- 42??

OpenStudy (anonymous):

tsk, tsk, tsk. my cherri: (x^3+8x^2)-(6x-48) x^2(x+8)-6(x-8), now you take it from there

OpenStudy (anonymous):

am I foiling this??

OpenStudy (anonymous):

now group the terms buddy: (x^2-6)(x+8)

OpenStudy (anonymous):

I get 2x^2+8x-6x+2 ??

OpenStudy (anonymous):

hello

OpenStudy (anonymous):

hello

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