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Mathematics 16 Online
OpenStudy (anonymous):

need help on the attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

was the last answer wrong?

OpenStudy (anonymous):

hkd d d d d d d dddddd i

OpenStudy (anonymous):

I'm nut sure but did you check all the graphs to make sure your first answer was correct

OpenStudy (anonymous):

oops! I misspelled not to nut,

OpenStudy (anonymous):

satellite where you at?

OpenStudy (anonymous):

i only saw three graphs. are there more?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

there 5 graphs to choose from

OpenStudy (anonymous):

hi

OpenStudy (anonymous):

ok it is still b i think

OpenStudy (anonymous):

you know that the second derivative is always positive. this tells you that the function is always concave up

OpenStudy (anonymous):

4 and 5 both have parts that are concave down. so they are out as well.

OpenStudy (anonymous):

OpenStudy (anonymous):

yeah i see them now. 3, 4, 5 all have parts that are concave down, but you are told that \[f''(x)>0\] for all x not equal 0, so your function must be concave up

OpenStudy (anonymous):

only 1 and 2 are always concave up, so it has to be the second one for the reason i stated earlier

OpenStudy (anonymous):

Thanks I could you help me on a similar problem dealing with finding the relative minimum on a graph

OpenStudy (anonymous):

OpenStudy (anonymous):

Relative min is where the function changes from decreasing to increasing, or where the derivative changes from negative to positive.

OpenStudy (anonymous):

correct

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