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Mathematics 19 Online
OpenStudy (anonymous):

need help on attachment

OpenStudy (anonymous):

OpenStudy (anonymous):

alright ta, now you understand the first derivative test correct

OpenStudy (anonymous):

this is just a visual derivative test... your zeroes will be your critical points because when the derivative is 0 and your tangent is a horizontal line

OpenStudy (anonymous):

and also you know that when the derivative changes from positive to negative... it makes a concave down hump which will create a maximum

OpenStudy (anonymous):

so looking at this graph you can see that the graph that where before the graph hits the zero it's positive and when it goes past the zero it goes negative... that will be your local max... it's backwards for you minimum in the case that if you see it going negative and then positive that will be a min

OpenStudy (anonymous):

so looking at the slope it goes from negative to positive at a showing that it is a minimum

OpenStudy (anonymous):

still don't really get your explanation of the graph being positive before the graph hits zero, are you talking about before its hits the first x-intercept which is a

OpenStudy (anonymous):

alright so you understand the derivative test correct?

OpenStudy (anonymous):

zero = x intercepts

OpenStudy (anonymous):

you can use zeroes and x intercepts interchangeably

OpenStudy (anonymous):

so the answer would be the critical points of b and c, since the gave is concave upward at those points

OpenStudy (anonymous):

That the local minimum

OpenStudy (anonymous):

not at point c. point c is a point of inflection. not a max or a min

OpenStudy (anonymous):

yes i know thats the tough one but b is not the min... it's the max

OpenStudy (anonymous):

because it's showing you the slope of the function so b is a max... because it is positive and then after the critical it goes negative

OpenStudy (anonymous):

a is your minimum

OpenStudy (anonymous):

why is it a, and c, or b

OpenStudy (anonymous):

oops! I meant not c or b

OpenStudy (anonymous):

the graph is going to look like this|dw:1281497576978:dw|

OpenStudy (anonymous):

alright so you know that the first derivative is your slope correct? and this graph is of your f' or basically is graphing the change of your slope

OpenStudy (anonymous):

I thought they gave us the graph of derivative

OpenStudy (anonymous):

it is.. .the derivative is your graph of your slope changing, so when on your f' graph you see a negative number it means that essentially the graph is decreasing and when it is positive the graph is increasing

OpenStudy (anonymous):

understand so far?

OpenStudy (anonymous):

so why is critcal point a an local minimum when its increasing to a local maximum

OpenStudy (anonymous):

it isn't if you look it's below the x axis meaning it's a - number

OpenStudy (anonymous):

so what b and c then?

OpenStudy (anonymous):

it just means that the slope is getting more i guess horizontal

OpenStudy (anonymous):

well before b your graph is showing that the slope is positive so it's looking like this|dw:1281497909031:dw|

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