Question

4p − 2q = 16,

5p + 7q = 1

Answer 1

in the first eqn
2p-q=16
in second
5p+7q=1
multiply 1sst by then add both eqn, you get
19p=56 then solve

Answer 2

sry in 1st its =8

Answer 3

2p-q=8
5p+7q=1
when eqn 1 multiplied by 7 and both are added, gives you
19p=56

Answer 4

sry 19p=57

Answer 5

solve the top for q by first subtracting 4 p
-2q=-4p+16

divide by -2

q=2p-8

put this into the second equation

5p+7(2p-8)=1

multiply it out and add like terms

5p+14p- 56 = 1

19p-56=1

add 56 to both sides

19p-56+56=1+56

19p=57

divide by 19 to get

p=3

then use this in either the first or second equation to find q (i chose the 2nd one)

5p+7q=1
5(3)+7q=1

15+7q=1

minus 15 both sides

-15+15+7q=1-15

7q=-14

divide by 7 to get
q=-2

check

5(3)+7(-2)=1
15-14=1
1=1

correct your answers are

p=3
q=-2

Answer 6

you get p=3
then substitute p in the first eqn
you get q=2p-8
=6-8
=-2
therefore, (p,q)=(3,-2)

Answer 7

thanks guys