Could someone please explain how to get answers a nd b below:

it has to be in the form of ax+b
than
y''=0
y'=a
y=ax+b
-2a+4(ax+b)=2+3x
4ax-2a+4b=2+3x

a=3/4
b=8/7

Question

Could someone please explain how to get answers a nd b below:

it has to be in the form of ax+b
than 
y''=0
y'=a
y=ax+b
-2a+4(ax+b)=2+3x
4ax-2a+4b=2+3x

a=3/4
b=8/7

anonymous · Answer

differentiate it once and twice, u get 2 eqs, solve them and u get a and b values

anonymous · Answer

can you show me the working

anonymous · Answer

Is this given in the question :
-2a+4(ax+b)=2+3x 4ax-2a+4b=2+3x 

or did u try to find these eqs??

anonymous · Answer

yeah its part of a differential equation question

anonymous · Answer

yeah thats correct, now differentiate the equations

anonymous · Answer

-2a+4(y)=2+3x ---> y=(2+3x+2a)/4

y' = 3/4 = a
b is just replacing in ax+b = (2+3x+2a)/4