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Mathematics 12 Online
OpenStudy (anonymous):

Identify the values of m that allows you to factor x^3+3x^2-x+m?

OpenStudy (anonymous):

correction: value of m...lol no s

OpenStudy (anonymous):

at first factor out x^2 from the first 2 terms and see what is left inside and how you can make the same expression for the 3rd and 4th terms.

OpenStudy (anonymous):

So x^2(x+3)-some number(x+m). Now in order to correctly factor by grouping, you have to have the same term in the parentheses so thus, x+3 is in parentheses and a negative one is factored out of it. Thus it factors to (x^2-1)(x+3). But were not done yet because there is a difference of two squares so we factor that out to (x-1)(x+1)(x+3). Now we are done.

OpenStudy (anonymous):

Does this correspond with your answer sheet?

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