Question

write the first four terms of the sequence for n=1,2,2 and 4
f(n)=6n^2

Answer 1

you just put those numbers in. 6(1)^2, 6(2)^2, 6(3)^2, 6(4)^2, which would be 36, 144, 324, 576

Answer 2

6(1)^2 = 6
6(2)^2= 24
6(3)^2= 54
6(4)^2= 96

elgen ur wrong

Answer 3

6*1^2=6*1=6
6*2^2=6*4=24
6*3^2=6*6=36
6*4^2=6*6=48

Answer 4

oops, that third one should have been 6*9=54

Answer 5

its not being multiplied by two, its being squared

Answer 6

ya so BOOM

Answer 7

oh lol, for some reason i read it as if they were in a parenthesis. probably should pay more attention, sorry friends :P

Answer 8

np, thanks for asking, now you know :D