Question

The sum of two integers is greater than 12. One integer is ten less than twice the other. What are the least values of the integers. The sum of two integers is greater than 12. One integer is ten less than twice the other. What are the least values of the integers. @Mathematics

Answer 1

it is greater than 5

Answer 2

i do not get this

Answer 3

X + Y = 12
X-10 = 2Y

Not sure if I'm correct but it might be a start.

Answer 4

only one mistake in first equation > will be there in place of equal to @MWSiOUX

Answer 5

x + y > 12
x = 2y - 10

2y - 11 + y > 12
3y > 23
y > 23/3
smallest integer = 8
y is 8.. x is 6

6

Answer 6

{x+y=13,x-10=2y}
{x = 12, y = 1}

Answer 7

10 less than twice the other would be x = 2y -10 not x -10 = 2y..

Answer 8

x+y>12
2x-10=y or 2y-10=x (not sure if we have enough info to solve)

Answer 9

"The sum of two integers is greater than 12" If the numbers are integers, then the sum must be at least 13.

Answer 10

If you solve for x you get x = 2y -10. substitute this for x in x + y > 12
2y - 10 + y > 12
3y -10 > 12 add 10
3y >22 ---> y>22/3
y has to be an integer and 22/3 is 7.333, so y = 8
x = 2(8) -10 = 6
y = 8, x = 6

Answer 11

@ EdgeOfTheEarth

Using your equations, Mathematica shows that there are five solutions for x and y where the total of x + y varies from 14 through 26 in increments of 3:

Table[ Solve[ {x+y==k,x==2 y-10}, {x,y} ], {k,14,26,3} ]

{{{x->6,y->8}},{{x->8,y->9}},{{x->10,y->10}},
{{x->12,y->11}},{{x->14,y->12}}}