Multiply 6-3 Square root 2 by its conjugate. What is the result?
\[6-3\sqrt{2}\] is the equation
(6-3sqrt2)(6+3sqrt2)... should give you 54
I'm sorry I was wrong. It is 18... Since the conjugate causes the last terms to be negative.
Yes, I figured it was 18. Just did the calculations thank you for your help! :)
Anytime :)
Would you happen to know the answer to this one 3 square root of 15 lies between two consecutive integers. What would the two consecutive integers be?
Yeah. Your result is 11.61. So your two integers would be 11 and 12
|dw:1319495473653:dw|\[\sqrt[3]{15}\]
is it 3 times root 15 or the 3rd root of 15
3rd root of 15
oh ok, then your answer is 2.466 so your two integers would be 2 and 3
That's what I got the first time, but I thought I was doing it incorrectly, thanks again :)
of course! Glad I could help
:)
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