Multiply 6-3 Square root 2 by its conjugate. What is the result?

Question

anonymous · Answer

$$6-3\sqrt{2}$$ is the equation

anonymous · Answer

(6-3sqrt2)(6+3sqrt2)... should give you 54

anonymous · Answer

I'm sorry I was wrong. It is 18... Since the conjugate causes the last terms to be negative.

anonymous · Answer

Yes, I figured it was 18. Just did the calculations thank you for your help! :)

anonymous · Answer

Anytime :)

anonymous · Answer

Would you happen to know the answer to this one 3 square root of 15 lies between two consecutive  integers.  What would the two consecutive integers be?

anonymous · Answer

Yeah. Your result is 11.61. So your two integers would be 11 and 12

anonymous · Answer

|dw:1319495473653:dw|$$\sqrt[3]{15}$$

anonymous · Answer

is it 3 times root 15 or the 3rd root of 15

anonymous · Answer

3rd root of 15

anonymous · Answer

oh ok, then your answer is 2.466 so your two integers would be 2 and 3

anonymous · Answer

That's what I got the first time, but I thought I was doing it incorrectly, thanks again :)

anonymous · Answer

of course! Glad I could help

anonymous · Answer

:)