Question

find the derivative of f(x)=cosh(lnx) by plugging lnx into the definition for hyperbolic cosine and simplifying before differentiating find the derivative of f(x)=cosh(lnx) by plugging lnx into the definition for hyperbolic cosine and simplifying before differentiating @Mathematics

Answer 1

cosh(ln(x))=(x^2+1)/2x
that's your first step according to the question.

Answer 2

how did you get that?

Answer 3

I see now, what should I do for the next step

Answer 4

cosh(x) = 1/2( e^-x+e^x)
that is one of the definitions of cosh
then plug in lnx for x
1/2( e^-lnx+e^lnx)
expand and junk

Answer 5

I would factor out a constant, then use the quotient rule. After that it should be pretty straightforward.