Question

Solve the equation.

x^4-x^2=2x^2+4

x= Solve the equation.

x^4-x^2=2x^2+4

x= @Mathematics

Answer 1

\[x^{4}-x^{2}=2x^{2}+4\]\[x^{4}-3x^{2}-4=0\]\[(x^{2}-4)(x^{2}+1)=0\]\[x=1, -1, 2, -2\]

Answer 2

Wow... Even I myself was shocked of the answer... lol

Answer 3

thanks for your speedy response

Answer 4

given, x^4-x^2=2x^2+4
or, x^4-3x^2-4=0
or, x^4-4x^2+x^2-4=0
or, x^2(x^2-4)+1(x^2-4)=0
or, (x^2-4)(x^2+1)=0
or, x=2,-2

Answer 5

1, and -1 are not real roots dont forget.

Answer 6

Well
\[1^{2}=1\]and \[(-1)^{2}=1\]
lol... Sorry

Answer 7

roots are 2,-2,i,-i

Answer 8

I just get it wrong sometimes :P