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Mathematics 18 Online
OpenStudy (anonymous):

find all intervals for which the graph of the function y=8x^3-2x^4 is concave downward. find all intervals for which the graph of the function y=8x^3-2x^4 is concave downward. @Mathematics

OpenStudy (anonymous):

Use the second derivatie test

OpenStudy (anonymous):

f'(x)=24x^2-8x^3 f''(x)=48x-24x^2

OpenStudy (anonymous):

alright, that sounds familiar but then what?

OpenStudy (anonymous):

find your inflection points by f''(x)=0

OpenStudy (anonymous):

f''(x) =0 ?

OpenStudy (anonymous):

okay got it, thanks.

OpenStudy (anonymous):

so the function is convex for x > x- inflection point

OpenStudy (anonymous):

wait what?

OpenStudy (anonymous):

yes your inflection points are when f''(x)=0

OpenStudy (anonymous):

i got inflection points x=0 and x=2

OpenStudy (anonymous):

alright so just like testing for max and mins take a point from each side of your inflection points if f''(c)>0 , it's concave upward f''(c)<0 , concave downwards

OpenStudy (anonymous):

so in this case i'd pick c=-1,1,3

OpenStudy (anonymous):

yeah that's what i did. I got x<0 and x>2. thanks for the help.

OpenStudy (anonymous):

so if you're looking for local minima and maxima, do you use the first or second derivative test?

OpenStudy (anonymous):

first

OpenStudy (anonymous):

to find the min/max take the crit pt of first derivative and put it in the original function

OpenStudy (anonymous):

to get the inflection point take the crit pt of the 2nd derivative and put it in the original eq

OpenStudy (anonymous):

okay thanks

OpenStudy (anonymous):

lia i forgot this will u plz explain it to me

OpenStudy (anonymous):

no problem

OpenStudy (anonymous):

explain the question or the solution?

OpenStudy (anonymous):

means solution

OpenStudy (anonymous):

after finding the first derivative, make f'(x)=0. after finding the solutions to that, use points in between the points that you found to see where the graph of f'(x) will be negative or positive. wherever it's negative, it is concave downward.

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

f''(x)=0 is for inflection points or concavity.. Max and mins are for f'(x)

OpenStudy (anonymous):

you can also use the 2nd dericative test dont forget. Where you take the crit points of f'(x) and plug them in to f''(x) which is easier way to test for relative extrema

OpenStudy (anonymous):

There are all kinds of test.... so yeah pick one and enjoy lol

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