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Dividing Exponents m3n3 ________ m4n4
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Do you mean: \[({m^{3}}{n^{3}})\div ({m^{4}}{n^{4}})\] There's a rule of exponents to the form of: \[{x^{a}}\div {x^{b}} = {x^{a-b}}\] Thus: \[({m^{3}}{n^{3}})\div ({m^{4}}{n^{4}})\]\[=({m^{-1}}{n^{-1}})\]\[=1 \div (mn)\]
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