Mathematics
OpenStudy (anonymous):

find the derivative of F(x)=(ln(3))^(cos(x))

OpenStudy (anonymous):

$\ln(3)^{\cos(x)}$

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

Write the equation like $y = \ln(3)^{\cos(x)}$

OpenStudy (anonymous):

-log(3)^(cos(x))*log(log(3))*sin(x)

OpenStudy (anonymous):

I think....

OpenStudy (anonymous):

i was thinking taking natural log on both sides but i dont think that would help??

OpenStudy (anonymous):

yeah it won't because i'm not solving for x, i'm just trying to find the derivative.

OpenStudy (anonymous):

i think it would.. lets try

OpenStudy (anonymous):

$\ln(y) = \cos(x) \ln(\ln(3))$

OpenStudy (anonymous):

My answer is correct. The chain rule I used is a little overly complicated though.

OpenStudy (anonymous):

$-\log(3)^{cosx}*(\log(\log(3))) *\sin(x)$

OpenStudy (anonymous):

is that what you think it is?

OpenStudy (anonymous):

u = cos(x); F'(x) = d(log^u(3))/du * du/dx; du/dx = -sin(x); d(log(3)^u)/du = log(3)^u * log(log(3)); F'(x) = log(3)^u * log(log(3)) * -sin(x)

OpenStudy (agreene):

$\ln (\ln 3) -\sin (x) \ln^{cos(x)}(3)$

OpenStudy (anonymous):

$ln(y) = -\ln(\ln(3))\sin(x)$

OpenStudy (anonymous):

$\frac{y \prime}{y} = -\ln(\ln(3))\sin(x)$

OpenStudy (anonymous):

$y \prime = y[-\ln(\ln(3))\sin(x)]$

OpenStudy (anonymous):

$y \prime = \ln(3)^{\cos(x)}[-\ln(\ln(3))\sin(x)]$

OpenStudy (anonymous):

Then i guess you would factor out the negative?

OpenStudy (agreene):

I prefer my answer. I chain ruled it.

OpenStudy (anonymous):

i'm confused on how you went from ln(y) to y'/y

OpenStudy (anonymous):

the derivative of $\ln(y)$ is $\frac{1}{y} * y \prime$

OpenStudy (anonymous):

i thought the derivative of ln(x)=(1/x)?

OpenStudy (anonymous):

It's the chain rule of that function. the derivative of ln(x) = 1/x, so using the chain rule with u = y, d(ln(u))/du * du/dx = 1/u * y' = y'/u = y'/y

OpenStudy (anonymous):

you have to use implicit differentiation because ln is a function of y

OpenStudy (anonymous):

or y is a function of ln.. how ever it goes

OpenStudy (anonymous):

y is a function of x.