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OpenStudy (anonymous):

y=8x^2-x^2-8 what symmetry does it fall on

OpenStudy (anonymous):

typo?

OpenStudy (amistre64):

-b/2a

OpenStudy (saifoo.khan):

x=0?

OpenStudy (amistre64):

lol

OpenStudy (anonymous):

That's an even function....

OpenStudy (anonymous):

maybe ? it says \[8x^2-x^2-8\] so it is either a typo, or you are supposed to write \[7x^2-8\] as a first step

OpenStudy (amistre64):

typo or not, its still gona be -b/2a yay!!

OpenStudy (saifoo.khan):

LOL.

OpenStudy (anonymous):

well not if it is \[8x^3-x^2-8\]

OpenStudy (amistre64):

harumph, it has no symmetry then

OpenStudy (saifoo.khan):

LOL.

OpenStudy (anonymous):

no typo

OpenStudy (anonymous):

here is one from the archives http://twitpic.com/554zvh i am proud to say that i gave it!

OpenStudy (amistre64):

what symmetry does it fall on, might mean a point

OpenStudy (amistre64):

good job ;)

OpenStudy (amistre64):

and after that they simply gave up shouting out medals ...

OpenStudy (saifoo.khan):

8x^2-x^2-8 7x^2 - 8 -b/2a -0/2a x= 0

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