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OpenStudy (anonymous):
y=8x^2-x^2-8 what symmetry does it fall on
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OpenStudy (anonymous):
typo?
OpenStudy (amistre64):
-b/2a
OpenStudy (saifoo.khan):
x=0?
OpenStudy (amistre64):
lol
OpenStudy (anonymous):
That's an even function....
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OpenStudy (anonymous):
maybe ? it says \[8x^2-x^2-8\] so it is either a typo, or you are supposed to write \[7x^2-8\] as a first step
OpenStudy (amistre64):
typo or not, its still gona be -b/2a yay!!
OpenStudy (saifoo.khan):
LOL.
OpenStudy (anonymous):
well not if it is \[8x^3-x^2-8\]
OpenStudy (amistre64):
harumph, it has no symmetry then
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OpenStudy (saifoo.khan):
LOL.
OpenStudy (anonymous):
no typo
OpenStudy (anonymous):
here is one from the archives http://twitpic.com/554zvh i am proud to say that i gave it!
OpenStudy (amistre64):
what symmetry does it fall on, might mean a point
OpenStudy (amistre64):
good job ;)
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OpenStudy (amistre64):
and after that they simply gave up shouting out medals ...
OpenStudy (saifoo.khan):
8x^2-x^2-8 7x^2 - 8 -b/2a -0/2a x= 0
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