Ask your own question, for FREE!
Mathematics 32 Online
OpenStudy (anonymous):

Do anybody know this? Show an equation and a solution for the problem. Arnold needs a 25% solution of nitric acid. He has 20 ml of a 30% solution. How many ml of a 15% solution should he add to obtain the required 25% solution?

OpenStudy (anonymous):

Let the amount of 15% solution required be = x ml ATQ xml of 15% + 20 ml of 30% = (x + 20) ml of 25% => x * 0.15 + 20*0.30 = (x + 20)*0.25 => 0.15x + 6 = 0.25x + 5 => 6 - 5 = 0.25x - 0.15x => 1 = 0.1x => 1/0.1 =x => x = 10 so 10 ml of 15% solution should he add to obtain the required 25% solution

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
brianagatica14: Any artist on here?
2 hours ago 7 Replies 2 Medals
Uniful3: Art dump..
4 hours ago 8 Replies 1 Medal
mimix: hii i miss everyone
1 day ago 4 Replies 0 Medals
hellokitty265: Art
22 hours ago 13 Replies 1 Medal
TarTar: Any Songwriters here???
9 hours ago 26 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!